{"id":33803,"date":"2019-10-31T21:54:45","date_gmt":"2019-10-31T18:54:45","guid":{"rendered":"https:\/\/prohoster.info\/blog\/on-vam-ne-drook\/"},"modified":"2019-10-31T21:54:45","modified_gmt":"2019-10-31T18:54:45","slug":"on-vam-ne-drook","status":"publish","type":"post","link":"https:\/\/prohoster.info\/hu\/blog\/administrirovanie\/on-vam-ne-drook","title":{"rendered":"\u0150 nem dRook","gt_translate_keys":[{"key":"rendered","format":"text"}]},"content":{"rendered":"<p>A Rook egyre n\u00f6vekv\u0151 n\u00e9pszer\u0171s\u00e9ge miatt szeretn\u00e9k besz\u00e9lni a h\u00e1tul\u00fct\u0151ir\u0151l \u00e9s a probl\u00e9m\u00e1kr\u00f3l, amelyekkel szembes\u00fclhet.<\/p>\n<p>R\u00f3lam: Ceph adminisztr\u00e1ci\u00f3s tapasztalat a hammer verzi\u00f3 \u00f3ta, k\u00f6z\u00f6ss\u00e9gi alap\u00edt\u00f3. <noindex><a rel=\"nofollow\" href=\"https:\/\/t.me\/ceph_ru\">t.me\/ceph_hu<\/a><\/noindex> a Telegramon.<\/p>\n<p>Annak \u00e9rdek\u00e9ben, hogy ne legyek alapos, hivatkozni fogok a Habr-on (a rangsor alapj\u00e1n!) l\u00e9v\u0151 probl\u00e9m\u00e1kra a ceph-el kapcsolatban. Ezekkel a probl\u00e9m\u00e1kkal \u00e9n is tal\u00e1lkoztam. Az anyagfelhaszn\u00e1l\u00e1s linkje a poszt v\u00e9g\u00e9n tal\u00e1lhat\u00f3.<\/p>\n<p>A Rook posztban nem v\u00e9letlen\u00fcl eml\u00edtj\u00fck a ceph-t \u2014 a Rook l\u00e9nyeg\u00e9ben a ceph Kubernetes-be csomagolva, teh\u00e1t \u00f6r\u00f6kli annak \u00f6sszes probl\u00e9m\u00e1j\u00e1t. A ceph probl\u00e9m\u00e1ival kezdj\u00fcnk.<br \/>\n<noindex><a rel=\"nofollow\" name=\"habracut\"><\/a><\/noindex><\/p>\n<h3>A klaszter kezel\u00e9s\u00e9nek egyszer\u0171s\u00edt\u00e9se<\/h3>\n<p>\nA Rook egyik el\u0151nye a ceph k\u00e9nyelmes kezel\u00e9se Kubernetes-en kereszt\u00fcl.<\/p>\n<p>Ugyanakkor a ceph t\u00f6bb mint 1000 param\u00e9tert tartalmaz a konfigur\u00e1l\u00e1shoz, m\u00edg a rook-on kereszt\u00fcl csak ezek egy kisebb r\u00e9sz\u00e9t m\u00f3dos\u00edthatjuk.<\/p>\n<blockquote><p>P\u00e9lda a Luminous-ra<br \/>\n&gt; ceph daemon mon.a config show | wc -l<br \/>\n1401<\/p><\/blockquote>\n<p><b>A Rook k\u00e9nyelmes m\u00f3dot k\u00edn\u00e1l a ceph telep\u00edt\u00e9s\u00e9re \u00e9s friss\u00edt\u00e9s\u00e9re.<\/b><br \/>\nA ceph Rook n\u00e9lk\u00fcl t\u00f6rt\u00e9n\u0151 telep\u00edt\u00e9se nem jelent probl\u00e9m\u00e1t \u2014 az ansible playbook 30 perc alatt elk\u00e9sz\u00fcl, de a friss\u00edt\u00e9s sor\u00e1n rengeteg probl\u00e9ma ad\u00f3dik. <\/p>\n<p><i>Id\u00e9zet a Krok posztj\u00e1b\u00f3l<\/i><\/p>\n<blockquote><p>P\u00e9lda: a crush tunables helytelen m\u0171k\u00f6d\u00e9se a hummer-r\u0151l jewel-re t\u00f6rt\u00e9n\u0151 friss\u00edt\u00e9s ut\u00e1n.<\/p>\n<p>&gt; ceph osd crush show-tunables<br \/>\n{<br \/>\n\u2026<br \/>\n \u00abstraw_calc_version\u00bb: 1,<br \/>\n \u00aballowed_bucket_algs\u00bb: 22,<br \/>\n \u00abprofile\u00bb: \u00abismeretlen\u00bb,<br \/>\n \u00aboptimal_tunables\u00bb: 0,<br \/>\n\u2026<br \/>\n}<\/p><\/blockquote>\n<p>De m\u00e9g a kisebb verzi\u00f3kon bel\u00fcl is akadnak probl\u00e9m\u00e1k.<\/p>\n<p>P\u00e9lda: a 12.2.6-os friss\u00edt\u00e9s a klasztert health err \u00e1llapotba \u00e9s l\u00e9nyeg\u00e9ben hib\u00e1s PG \u00e1llapotba hozza. <br \/>\n<noindex><a rel=\"nofollow\" href=\"https:\/\/ceph.com\/releases\/v12-2-8-released\/\">ceph.com\/releases\/v12-2-8-released<\/a><\/noindex><\/p>\n<p>Ne friss\u00edtse, v\u00e1rjon \u00e9s teszteljen? De \u00fagy t\u0171nik, a Rook-ot a friss\u00edt\u00e9sek k\u00e9nyelme \u00e9rdek\u00e9ben haszn\u00e1ljuk.<\/p>\n<h3>A klaszter disaster recovery neh\u00e9zs\u00e9gei a Rook-ban <\/h3>\n<p>\nP\u00e9lda: Az OSD le\u00e1ll, hib\u00e1kat dob\u00e1lva. Gyan\u00edtja, hogy a probl\u00e9ma a konfigur\u00e1ci\u00f3 egyik param\u00e9ter\u00e9ben van, szeretn\u00e9 megv\u00e1ltoztatni a konfigur\u00e1ci\u00f3t egy adott d\u00e9mon sz\u00e1m\u00e1ra, de nem tudja, mert Kubernetes-\u00e9t haszn\u00e1l, \u00e9s DaemonSet-tel rendelkezik.<\/p>\n<p>Nincs alternat\u00edva. A ceph tell osd.Num injectargs nem m\u0171k\u00f6dik \u2014 az OSD le van \u00e1llva.<\/p>\n<h3>A debug neh\u00e9zs\u00e9gei<\/h3>\n<p>\nN\u00e9h\u00e1ny be\u00e1ll\u00edt\u00e1s \u00e9s teljes\u00edtm\u00e9nyteszt \u00e9rdek\u00e9ben k\u00f6zvetlen\u00fcl az osd d\u00e9mon aljzat\u00e1hoz kell csatlakozni. Rook eset\u00e9n el\u0151sz\u00f6r meg kell tal\u00e1lni a sz\u00fcks\u00e9ges kont\u00e9nert, majd bel\u00e9pni abba, felfedezni a debug tooling hi\u00e1ny\u00e1t, \u00e9s nagyon csal\u00f3dottnak lenni.<\/p>\n<h3>Az OSD folyamatos emelked\u00e9s\u00e9nek neh\u00e9zs\u00e9gei<\/h3>\n<p>\nP\u00e9lda: Az OSD OOM miatt le\u00e1ll, megkezd\u0151dik az \u00fajraoszt\u00e1s, ezut\u00e1n a k\u00f6vetkez\u0151k is le\u00e1llnak.<\/p>\n<p>Megold\u00e1s: Az OSD-t egyes\u00e9vel ind\u00edtsa, v\u00e1rjon, am\u00edg teljesen csatlakozik a klaszterhez, majd ind\u00edtsa el a k\u00f6vetkez\u0151ket. (Tov\u00e1bbi inform\u00e1ci\u00f3k a Ceph. A katasztr\u00f3f\u00e1k anat\u00f3mi\u00e1ja c\u00edm\u0171 jelent\u00e9sben.)<\/p>\n<p>Bare metal telep\u00edt\u00e9s eset\u00e9n ezt k\u00e9zzel kell elv\u00e9gezni, Rook eset\u00e9n egy OSD-vel a noden \u00e1ltal\u00e1ban nincsenek probl\u00e9m\u00e1k, de ha OSD &gt; 1 van a noden, akkor probl\u00e9m\u00e1k l\u00e9phetnek fel a sorrendis\u00e9g miatt. <\/p>\n<p>Term\u00e9szetesen ezek megoldhat\u00f3k, de a Rookot a leegyszer\u0171s\u00edt\u00e9s \u00e9rdek\u00e9ben haszn\u00e1ljuk, m\u00edg bonyolults\u00e1got kapunk.<\/p>\n<h3>A ceph d\u00e9monok limitjeinek kiv\u00e1laszt\u00e1s\u00e1nak neh\u00e9zs\u00e9ge<\/h3>\n<p>\nBare metal telep\u00edt\u00e9s eset\u00e9n a sz\u00fcks\u00e9ges er\u0151forr\u00e1sok k\u00f6nnyen kisz\u00e1m\u00edthat\u00f3k a klaszterhez \u2014 l\u00e9teznek k\u00e9pletek \u00e9s kutat\u00e1sok. Gyeng\u00e9bb CPU-k haszn\u00e1lata eset\u00e9n m\u00e9gis sz\u00e1mos teljes\u00edtm\u00e9nytesztet kell elv\u00e9geznie, hogy meg\u00e9rtse mi a Numa, de ez m\u00e9g mindig egyszer\u0171bb, mint a Rook eset\u00e9ben.<\/p>\n<p>Rook eset\u00e9ben nemcsak a mem\u00f3riakorl\u00e1tok vannak, amelyeket meg lehet hat\u00e1rozni, hanem a CPU korl\u00e1toz\u00e1s\u00e1nak be\u00e1ll\u00edt\u00e1s\u00e1nak k\u00e9rd\u00e9se is felmer\u00fcl.<\/p>\n<p>Itt pedig sokat kell dolgoznia a teljes\u00edtm\u00e9nytesztekkel. Ha a korl\u00e1tokat al\u00e1becs\u00fcli, akkor lass\u00fa klasztert kap, ha unlimitet \u00e1ll\u00edt be, akkor akt\u00edv CPU haszn\u00e1latot kap a rebalance sor\u00e1n, ami rosszul hat a Kubernetesben fut\u00f3 alkalmaz\u00e1saira.<\/p>\n<h3>H\u00e1l\u00f3zati interakci\u00f3s probl\u00e9m\u00e1k v1<\/h3>\n<p>\nCeph eset\u00e9n 2x10 Gb-os h\u00e1l\u00f3zat haszn\u00e1lata aj\u00e1nlott. Az egyiket a kliensforgalomra, a m\u00e1sikat pedig a ceph szolg\u00e1ltat\u00e1si ig\u00e9nyeire (rebalance) haszn\u00e1lj\u00e1k. Ha bare metal ceph-t haszn\u00e1l, akkor ezt a feloszt\u00e1st k\u00f6nnyen be\u00e1ll\u00edthatja, ha Rookkal \u00e9l, akkor a h\u00e1l\u00f3zatok k\u00f6z\u00f6tti feloszt\u00e1s probl\u00e9m\u00e1kat okozhat, mivel nem minden klaszter konfigur\u00e1ci\u00f3 engedi meg a k\u00e9t k\u00fcl\u00f6nb\u00f6z\u0151 h\u00e1l\u00f3zat bet\u00e1pl\u00e1l\u00e1s\u00e1t egy podba.<\/p>\n<h3>H\u00e1l\u00f3zati interakci\u00f3s probl\u00e9m\u00e1k v2<\/h3>\n<p>\nHa nem v\u00e1lasztja sz\u00e9t a h\u00e1l\u00f3zatokat, akkor rebalance sor\u00e1n a ceph forgalma el\u00e1rasztja az eg\u00e9sz csatorn\u00e1t, \u00e9s a Kubernetesben fut\u00f3 alkalmaz\u00e1sai akadozni fognak vagy le\u00e1llnak. Cs\u00f6kkentheti a ceph rebalance sebess\u00e9g\u00e9t, de ezzel a hosszabb rebalance miatt megn\u0151 a kock\u00e1zata annak, hogy a m\u00e1sodik node kil\u00e9p a klaszterb\u0151l a lemezek vagy OOM miatt, ami garant\u00e1lt read only \u00e1llapotot eredm\u00e9nyez a klaszterre.<\/p>\n<h3>Hossz\u00fa rebalance \u2014 hossz\u00fa alkalmaz\u00e1sakad\u00e1s<\/h3>\n<p>\n<i>Id\u00e9zet a Ceph. A katasztr\u00f3f\u00e1k anat\u00f3mi\u00e1ja c\u00edm\u0171 bejegyz\u00e9sb\u0151l.<\/i><\/p>\n<blockquote><p>A tesztklaszter teljes\u00edtm\u00e9nye:<\/p>\n<p>A 4 Kbyte m\u00e9ret\u0171 \u00edr\u00e1si m\u0171velet 1 ms-ot vesz ig\u00e9nybe, 1000 m\u0171velet\/m\u00e1sodperc teljes\u00edtm\u00e9ny 1 sz\u00e1lon.<\/p>\n<p>A 4 Mbyte (objektumm\u00e9ret) m\u00e9ret\u0171 m\u0171velet 22 ms-ot vesz ig\u00e9nybe, 45 m\u0171velet\/m\u00e1sodperc teljes\u00edtm\u00e9ny.<\/p>\n<p>Teh\u00e1t, amikor az egyik dom\u00e9nb\u0151l h\u00e1rom meghib\u00e1sodik, a klaszter egy ideig degrad\u00e1lt \u00e1llapotban marad, \u00e9s a forr\u00f3 objektumok fele k\u00fcl\u00f6nb\u00f6z\u0151 verzi\u00f3k k\u00f6z\u00f6tt oszlik meg, \u00edgy a feljegyz\u00e9sek fele k\u00e9nyszer\u00edtett helyre\u00e1ll\u00edt\u00e1ssal kezd\u0151dik.<\/p>\n<p>A k\u00e9nyszer\u00edtett helyre\u00e1ll\u00edt\u00e1s idej\u00e9t k\u00f6r\u00fclbel\u00fcl \u00edgy sz\u00e1m\u00edtjuk ki \u2014 feljegyz\u00e9si m\u0171veletek a degrad\u00e1lt objektumban.<\/p>\n<p>El\u0151sz\u00f6r 4 MB-ot olvasunk 22 ms alatt, \u00edrunk 22 ms-ot, majd 1 ms alatt 4 kB adatot. Teh\u00e1t \u00f6sszesen 45 ms egy feljegyz\u00e9s v\u00e9grehajt\u00e1s\u00e1hoz a degrad\u00e1lt objektumban SSD-n, amikor a norm\u00e1l teljes\u00edtm\u00e9ny\u00fcnk 1 ms volt \u2014 a teljes\u00edtm\u00e9ny cs\u00f6kken\u00e9se 45-sz\u00f6r\u00f6s.<\/p>\n<p>Min\u00e9l nagyobb a degrad\u00e1lt objektumok ar\u00e1nya, ann\u00e1l ijeszt\u0151bb lesz a helyzet.<\/p><\/blockquote>\n<p> Kider\u00fcl, hogy a rebalance sebess\u00e9ge kritikus a klaszter helyes m\u0171k\u00f6d\u00e9s\u00e9hez.<\/p>\n<h3>Szerver-specifikus be\u00e1ll\u00edt\u00e1sok a ceph-hez<\/h3>\n<p>\nA ceph speci\u00e1lis hoszt tuningot ig\u00e9nyelhet. <\/p>\n<p>P\u00e9lda: sysctl be\u00e1ll\u00edt\u00e1sok \u00e9s a JumboFrame, ezek egy r\u00e9sze negat\u00edvan befoly\u00e1solhatja a payload-j\u00e1t.<\/p>\n<h3>A Rook val\u00f3di sz\u00fcks\u00e9glete k\u00e9rd\u00e9ses marad<\/h3>\n<p>\nHa felh\u0151ben dolgozik, rendelkezik a felh\u0151szolg\u00e1ltat\u00f3j\u00e1t\u00f3l sz\u00e1rmaz\u00f3 t\u00e1rol\u00f3val, ami sokkal k\u00e9nyelmesebb. <\/p>\n<p>Ha a saj\u00e1t szerverein van, a ceph kezel\u00e9se k\u00f6nnyebb lesz Kubernetes n\u00e9lk\u00fcl. <\/p>\n<p>K\u00f6lcs\u00f6n\u00f6z szervereket valamelyik olcs\u00f3bb hoszting szolg\u00e1ltat\u00f3t\u00f3l? Akkor sok izgalom v\u00e1r \u00d6nre a h\u00e1l\u00f3zattal, a k\u00e9s\u00e9sekkel \u00e9s a s\u00e1vsz\u00e9less\u00e9ggel kapcsolatban, ami nyilv\u00e1nval\u00f3an negat\u00edvan befoly\u00e1solja a ceph-t.<\/p>\n<p><b>\u00d6sszesen:<\/b> A Kubernetes bevezet\u00e9se \u00e9s a t\u00e1rol\u00e1s bevezet\u00e9se k\u00fcl\u00f6n feladatok, k\u00fcl\u00f6n bemenetekkel \u00e9s k\u00fcl\u00f6nb\u00f6z\u0151 megold\u00e1si lehet\u0151s\u00e9gekkel \u2014 ezek kever\u00e9se vesz\u00e9lyes trade-off-ot jelenthet az egyik vagy a m\u00e1sik \u00e9rdek\u00e9ben. Az ilyen d\u00f6nt\u00e9sek kombin\u00e1l\u00e1sa nagyon neh\u00e9z lesz a tervez\u00e9si f\u00e1zisban, \u00e9s m\u00e9g van egy \u00fczemel\u00e9si id\u0151szak is.<\/p>\n<p>Felhaszn\u00e1lt irodalom:<\/p>\n<p><noindex><a rel=\"nofollow\" href=\"https:\/\/habr.com\/ru\/company\/croccloudteam\/blog\/422905\/\">Bejegyz\u00e9s #1<\/a><\/noindex> \u00c9s \u00d6n a Cephr\u0151l besz\u00e9l\u2026 de t\u00e9nyleg olyan j\u00f3?<br \/>\n<noindex><a rel=\"nofollow\" href=\"https:\/\/habr.com\/ru\/company\/oleg-bunin\/blog\/431536\/\">Bejegyz\u00e9s #2<\/a><\/noindex> Ceph. A katasztr\u00f3fa anat\u00f3mi\u00e1ja<br \/>\n<br \/>Forr\u00e1s: <a content=\"nofollow\" rel=\"nofollow\" href=\"https:\/\/habr.com\/ru\/post\/452174\/\">habr.com<\/a><\/p>","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"excerpt":{"rendered":"<p>\u0412 \u0441\u0432\u044f\u0437\u0438 \u0441 \u043d\u0430\u0431\u0438\u0440\u0430\u044e\u0449\u0435\u0439 \u043f\u043e\u043f\u0443\u043b\u044f\u0440\u043d\u043e\u0441\u0442\u044c\u044e Rook \u0445\u043e\u0447\u0435\u0442\u0441\u044f \u043f\u043e\u0433\u043e\u0432\u043e\u0440\u0438\u0442\u044c \u043e \u0435\u0433\u043e \u043f\u043e\u0434\u0432\u043e\u0434\u043d\u044b\u0445 \u043a\u0430\u043c\u043d\u044f\u0445 \u0438 \u043f\u0440\u043e\u0431\u043b\u0435\u043c\u0430\u0445, \u043a\u043e\u0442\u043e\u0440\u044b\u0435 \u0436\u0434\u0443\u0442 \u0432\u0430\u0441 \u043d\u0430 \u043f\u0443\u0442\u0438. \u041e \u0441\u0435\u0431\u0435: \u041e\u043f\u044b\u0442 \u0430\u0434\u043c\u0438\u043d\u0438\u0441\u0442\u0440\u0438\u0440\u043e\u0432\u0430\u043d\u0438\u044f ceph \u0441 \u0432\u0435\u0440\u0441\u0438\u0438 hammer, \u043e\u0441\u043d\u043e\u0432\u0430\u0442\u0435\u043b\u044c \u043a\u043e\u043c\u044c\u044e\u043d\u0438\u0442\u0438 t.me\/ceph_ru \u0432 \u0442\u0435\u043b\u0435\u0433\u0440\u0430\u043c. \u0414\u0430\u0431\u044b \u043d\u0435 \u0431\u044b\u0442\u044c \u0433\u043e\u043b\u043e\u0441\u043b\u043e\u0432\u043d\u044b\u043c \u044f \u0431\u0443\u0434\u0443 \u0441\u0441\u044b\u043b\u0430\u0442\u044c\u0441\u044f \u043d\u0430 \u043f\u0440\u0438\u043d\u044f\u0442\u044b\u0435 \u0445\u0430\u0431\u0440\u043e\u043c (\u0441\u0443\u0434\u044f \u043f\u043e \u0440\u0435\u0439\u0442\u0438\u043d\u0433\u0443) \u043f\u043e\u0441\u0442\u044b \u043e \u043f\u0440\u043e\u0431\u043b\u0435\u043c\u0430\u0445 \u0441 ceph. \u0421 \u0431\u041e\u043b\u044c\u0448\u0435\u0439 \u0447\u0430\u0441\u0442\u044c\u044e \u043f\u0440\u043e\u0431\u043b\u0435\u043c \u0432 [&hellip;]<\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[688],"tags":[],"class_list":["post-33803","post","type-post","status-publish","format-standard","hentry","category-administrirovanie"],"aioseo_notices":[],"aioseo_head":"\n\t\t<!-- All in One SEO 5.0.3 - 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