🥇Roguelike basis konsol dina C++

perkenalan

"Linux sanés kanggo kaulinan!" mangrupa frase luntur: ayeuna aya loba kaulinan éndah husus dirancang pikeun sistem éndah ieu. Tapi sakapeung, anjeun hoyong anu khusus, anu pas pikeun anjeun ... Sareng kuring mutuskeun pikeun nyiptakeun anu khusus.

dasar

Kuring moal némbongkeun sarta ngabejaan Anjeun sakabéh kode (teu pisan metot) - ngan titik utama.

1.Karakter

Kabéh parameter karakter (kaséhatan, armor, pangalaman, jeung sajabana) didaptarkeun di dieu. Anu dipikaresep nyaéta gambar sareng arah gerakan (anu ayeuna henteu aya).

int x = 5, y = 5;
    hp = 100,
    maxhp = 100,
    dm    = 20,
    armor = 0,
    xp    = 0,
    level = 0,
    diff  = 10, // сложность
    pos   = 0; // направление

bool reg = 0,
       Mdm = 0, // бонусы
       ght = 0;

string color; // цвет будет использован в качестве индикатора состаяния героя

void hero()  // здесь происходит перемещение героя на координаты (x ; y)
{
  cout << "e[u " << "e[0;0H"; // восстановление позиции курсора, затирание пробелом
  for (int i = 0; i <= x; i++)
    cout << RIGHT;              // макрос "e[1C"
  for (int i = 0; i <= y; i++)
    cout << DOWN;             // макрос "e[1B"
  cout << "e[s" << color << "╬"; // сохранение позиции курсора
}

2. Manajemén

Kumaha carana mindahkeun karakter geus jelas (x-++, y-++). Tapi penanganan keyboard langkung narik:

char key;
char getkey()
{
  system("stty raw");
  key = getchar();
  system("stty cooked");
  return key;
}

Sadaya anu tinggaleun nyaéta nyetél "karakter kontrol." Ieu bisa dipigawé kalayan switch, tapi hate eta.

switch(...) case .. : ... ; break Hadé sapertos kieu

#define KEY if (key ==
#define I ){
#define J ;}else

void keys()
{
  getkey();
    KEY 'a' I x-- ; pos = 1 J
    KEY......
}

Geulis! Urang nuju looping fungsi jeung ngagulung sabudeureun layar! Tapi rada nyentak... Kursor terus kedip-kedip, kitu deui hurup-hurupna... Urang ngalereskeun!

//До цикла
  cout << "e[?25l"; //отключаем отображение курсора
  system("stty -echo"); //отключаем эхо-ввод
  system("xset r rate 120 10"); // изменяем задержку на более плавную
//После цикла
//-------Return_normal_system_settings--------
  cout << "e[00m";
  system("reset");
  system("xset r rate 200 20");

Péh! Hiji persen siap!

3. Dunya sabudeureun urang

Di dieu urang nyieun arrays pikeun x, y potongan dunya jeung potongan sorangan (char o[N]), sarua keur monster jeung bonus.

Jieun fungsi world(int objx[N] .... objy[N] ... obj[N], ... objcolor[N]) ku analogi jeung hero(), Tapi kalayan parameter jeung loop tambahan pikeun outputting Asép Sunandar Sunarya ... keur senang, urang ngagambar ukur dina widang view (vis) (if (ox[k] < vis && oy[k]....))

Ayeuna urang ngeusian layar ku partikel dunya nganggo kamar sareng petikan anu saderhana sareng sacara prosedural, dina waktos anu sami urang lebetkeun musuh sareng objék, pikeun acak lengkep kami henteu hilap. srand(time(NULL));

//------------------GENERATION---------------
void rooms()
{
  for (int i = 0; i <= 50; i++)
  {
    px[i] = rand() % 115 + 2;
    py[i] = rand() % 34 + 2;
    pl[i] = rand() % 5 + 5;
    ph[i] = rand() % 5 +  5;

    if (px[i] + pl[i] > 117) px[i] = 50 - pl[i] / 2; else
    if (px[i] < 2)           px[i] = 50 - pl[i] / 2; else
    if (py[i] < 1)           py[i] = 15 - ph[i] / 2; else
    if (py[i] + ph[i] > 37)  py[i] = 15 - ph[i] / 2;

    for (int j = 0; j <= i; j++)
    {
      while (px[i] > px[j] && px[i] < px[j] + pl[j])
        (px[i]+pl[i]/2 >= 55) ? px[i]++ : px[i]-- ;

      while (py[i] > py[j] && py[i] < py[j] + ph[j])
        (py[i]+ph[i]/2 >= 18) ? py[i]++ : py[i]-- ;

      while (px[i]+pl[i] > px[j] && px[i]+pl[i] < px[j] + pl[j])
        (px[i]+pl[i]/2 >= 55) ? px[i]++ : px[i]-- ;

      while (py[i]+ph[i] > py[j] && py[i]+ph[i] < py[j] + ph[j])
        (py[i]+ph[i]/2 >= 18) ? py[i]++ : py[i]-- ;
    }

    for (int j = 0; j <= i; j++)
    {
      while (px[j] + pl[j] >= 116) px[j]-- ;
      while (px[j] < 2)            px[j]++ ;
      while (py[j] < 1)            py[j]++ ;
      while (py[j] + ph[j] >= 37)  py[j]-- ;
    }
    tx[i] = px[i]+10; ty[i] = py[i]-3;

    if (i <= diff)
    {
      ex[i]  = px[i];
      ey[i]  = py[i];
      while (ex[i] < 10){ ex[i]++ ; epos[i] = 3 ;}
      while (ey[i] < 10){ ey[i]++ ; epos[i] = 1 ;}
      e[i]   = evar[pl[i]];
      ecolor[i] = "e[00me[31m";

      edm[i] = edmvar[pl[i]];
      ehp[i] = ehpvar[pl[i]];
      exp[i] = expvar[pl[i]];
    }
    rect(px[i], py[i], pl[i], ph[i]);
  }
}

void corrs()
{
  int pc, px, py;
  for (int i = 0; i <= 4; i++)
  {
    if (i < 2){
      px = 3;
      py = rand() % 33 + 3;
      pc = 110;
      line(px, py, pc, true);
      line(px, py+1, pc, true);
    } else {
      px = rand() % 100 + 3;
      py = 3;
      pc = 33;
      line(px, py, pc, false);
      line(px+1, py, pc, false);
    }
  }
}

4. Interaksi

Ayeuna urang kudu kumaha bae ulah ngaliwatan tembok jeung monster jeung meunang bonus ti item.

Paporit kami kanggo sareng #define

#define TOUCH if (x == ox[i] && y == oy[i] && pos ==
#define HIT   x == ex[i] && y == ey[i] && pos ==
 for (int i = 0; i <= n; i++)
  {
    if (i <= diff)
    {
     if (Mdm) ehp[i]-=2 ; // если бонус "массовый урон" включен
     epos[i] = 0;

     if (ex[i] < x+5 && ex[i] > x-5 &&
         ey[i] < y+5 && ey[i] > y-5  )
     {
       edel(i); // функция переписывающая предыдущее положение противника
       if (ex[i] < x I ex[i]++ ; epos[i] = 1 J
       if (ex[i] > x I ex[i]-- ; epos[i] = 2 J
       if (ey[i] < y I ey[i]++ ; epos[i] = 3 J
       if (ey[i] > y I ey[i]-- ; epos[i] = 4 ;}
     }
   for (int j = 0; j <= n; j++) // столкновение моба со стенками
       while (ex[i] == ox[j] && ey[i] == oy[j] || ex[i] == ex[j] && ey[i] == ey[j] && j != i)
       {
         if (epos[i] == 1) ex[i]-- ; else
         if (epos[i] == 2) ex[i]++ ; else
         if (epos[i] == 3) ey[i]-- ; else
         if (epos[i] == 4) ey[i]++ ;
       }

     if (x == ex[i] && y == ey[i]) //  "битва"
      {
       if (ehp[i] > 1)
       {
         ehp[i] -= dm;
         (edm[i] < armor) ?
         hp -= 0 :
         hp -= edm[i]-armor;
       } else {
         ex[i] = ey[i] = -1;
         xp += exp[i];
         ehp[i] = 12;
       }
     }
     if (!ght) // если не призрак проверять столкновение игрока с врагами
     {
       if (HIT 1) y++ ;else
       if (HIT 2) x-- ;else
       if (HIT 3) y-- ;else
       if (HIT 4) x++ ;
     }
    }
    if (!ght) // то же, но со стенами
    {
      TOUCH 1 I y++ J
      TOUCH 2 I x-- J
      TOUCH 3 I y-- J
      TOUCH 4 ) x++ ;
    }
  }

5. ménu

Urang saukur mintonkeun menu dina layar, jumlah item, jeung prosés pilihan pamuter urang ngagunakeun getkey (). Urang nulis status bar karakter, nerapkeun menu leveling, nulis backstory a, sarta mungkas nepi ka naon Kuring geus dubbed "Subsoil".