perkenalan
"Linux sanés kanggo kaulinan!" - hiji frase luntur: ayeuna aya loba kaulinan éndah husus pikeun sistem éndah ieu. Tapi tetep, sakapeung anjeun hoyong anu khusus anu cocog sareng anjeun ... Sareng kuring mutuskeun pikeun nyiptakeun hal anu khusus ieu.
dasar
Kuring moal némbongkeun sarta ngabejaan sakabeh kode (teu pisan metot) - ngan titik utama.
1.Karakter
Kabéh parameter karakter dibéréndélkeun di dieu (kaséhatan, armor, pangalaman, jeung sajabana) Minat teh gambar jeung arah gerakan (nu ayeuna teu sadia).
int x = 5, y = 5;
hp = 100,
maxhp = 100,
dm = 20,
armor = 0,
xp = 0,
level = 0,
diff = 10, // сложность
pos = 0; // направление
bool reg = 0,
Mdm = 0, // бонусы
ght = 0;
string color; // цвет будет использован в качестве индикатора состаяния героя
void hero() // здесь происходит перемещение героя на координаты (x ; y)
{
cout << "e[u " << "e[0;0H"; // восстановление позиции курсора, затирание пробелом
for (int i = 0; i <= x; i++)
cout << RIGHT; // макрос "e[1C"
for (int i = 0; i <= y; i++)
cout << DOWN; // макрос "e[1B"
cout << "e[s" << color << "╬"; // сохранение позиции курсора
}
2. Manajemén
Cara mindahkeun karakterna tos jelas (x—++, y—++). Tapi ngolah keyboard langkung narik:
char key;
char getkey()
{
system("stty raw");
key = getchar();
system("stty cooked");
return key;
}
Sadaya anu tetep nyaéta nyetél "karakter kontrol". Anjeun tiasa ngalakukeun hal eta ngagunakeun switch, tapi hate eta.
switch(...) case .. : ... ; break langkung sae sapertos kieu
#define KEY if (key ==
#define I ){
#define J ;}else
void keys()
{
getkey();
KEY 'a' I x-- ; pos = 1 J
KEY......
}
kageulisan! Fungsi loop sareng ngajalankeun sabudeureun layar! Tapi kumaha bae eta rada kasar ... Jeung kursor flashes, sarta hurup ... Urang bakal ngalereskeun eta!
//До цикла
cout << "e[?25l"; //отключаем отображение курсора
system("stty -echo"); //отключаем эхо-ввод
system("xset r rate 120 10"); // изменяем задержку на более плавную
//После цикла
//-------Return_normal_system_settings--------
cout << "e[00m";
system("reset");
system("xset r rate 200 20");
Wow! Hiji persen geus siap!
3. Dunya sabudeureun urang
Di dieu urang nyieun arrays pikeun x, y potongan dunya jeung potongan sorangan (char o[N]), sarua keur monster jeung bonus.
Jieun fungsi world(int objx[N] .... objy[N] ... obj[N], ... objcolor[N]) ku analogi jeung hero(), Tapi kalayan parameter jeung loop tambahan pikeun outputting Asép Sunandar Sunarya ... keur senang, urang ngagambar ukur dina widang view (vis) (if (ox[k] < vis && oy[k]....))
Ayeuna urang ngeusian layar ku partikel dunya nganggo kamar sareng petikan anu saderhana sareng sacara prosedural, dina waktos anu sami urang lebetkeun musuh sareng objék, pikeun acak lengkep kami henteu hilap. srand(time(NULL));
//------------------GENERATION---------------
void rooms()
{
for (int i = 0; i <= 50; i++)
{
px[i] = rand() % 115 + 2;
py[i] = rand() % 34 + 2;
pl[i] = rand() % 5 + 5;
ph[i] = rand() % 5 + 5;
if (px[i] + pl[i] > 117) px[i] = 50 - pl[i] / 2; else
if (px[i] < 2) px[i] = 50 - pl[i] / 2; else
if (py[i] < 1) py[i] = 15 - ph[i] / 2; else
if (py[i] + ph[i] > 37) py[i] = 15 - ph[i] / 2;
for (int j = 0; j <= i; j++)
{
while (px[i] > px[j] && px[i] < px[j] + pl[j])
(px[i]+pl[i]/2 >= 55) ? px[i]++ : px[i]-- ;
while (py[i] > py[j] && py[i] < py[j] + ph[j])
(py[i]+ph[i]/2 >= 18) ? py[i]++ : py[i]-- ;
while (px[i]+pl[i] > px[j] && px[i]+pl[i] < px[j] + pl[j])
(px[i]+pl[i]/2 >= 55) ? px[i]++ : px[i]-- ;
while (py[i]+ph[i] > py[j] && py[i]+ph[i] < py[j] + ph[j])
(py[i]+ph[i]/2 >= 18) ? py[i]++ : py[i]-- ;
}
for (int j = 0; j <= i; j++)
{
while (px[j] + pl[j] >= 116) px[j]-- ;
while (px[j] < 2) px[j]++ ;
while (py[j] < 1) py[j]++ ;
while (py[j] + ph[j] >= 37) py[j]-- ;
}
tx[i] = px[i]+10; ty[i] = py[i]-3;
if (i <= diff)
{
ex[i] = px[i];
ey[i] = py[i];
while (ex[i] < 10){ ex[i]++ ; epos[i] = 3 ;}
while (ey[i] < 10){ ey[i]++ ; epos[i] = 1 ;}
e[i] = evar[pl[i]];
ecolor[i] = "e[00me[31m";
edm[i] = edmvar[pl[i]];
ehp[i] = ehpvar[pl[i]];
exp[i] = expvar[pl[i]];
}
rect(px[i], py[i], pl[i], ph[i]);
}
}
void corrs()
{
int pc, px, py;
for (int i = 0; i <= 4; i++)
{
if (i < 2){
px = 3;
py = rand() % 33 + 3;
pc = 110;
line(px, py, pc, true);
line(px, py+1, pc, true);
} else {
px = rand() % 100 + 3;
py = 3;
pc = 33;
line(px, py, pc, false);
line(px+1, py, pc, false);
}
}
}
4. Interaksi
Ayeuna urang kudu kumaha bae ulah ngaliwatan tembok jeung monster sarta nampa bonus ti barang.
Paporit kami kanggo sareng #define
#define TOUCH if (x == ox[i] && y == oy[i] && pos ==
#define HIT x == ex[i] && y == ey[i] && pos ==
for (int i = 0; i <= n; i++)
{
if (i <= diff)
{
if (Mdm) ehp[i]-=2 ; // если бонус "массовый урон" включен
epos[i] = 0;
if (ex[i] < x+5 && ex[i] > x-5 &&
ey[i] < y+5 && ey[i] > y-5 )
{
edel(i); // функция переписывающая предыдущее положение противника
if (ex[i] < x I ex[i]++ ; epos[i] = 1 J
if (ex[i] > x I ex[i]-- ; epos[i] = 2 J
if (ey[i] < y I ey[i]++ ; epos[i] = 3 J
if (ey[i] > y I ey[i]-- ; epos[i] = 4 ;}
}
for (int j = 0; j <= n; j++) // столкновение моба со стенками
while (ex[i] == ox[j] && ey[i] == oy[j] || ex[i] == ex[j] && ey[i] == ey[j] && j != i)
{
if (epos[i] == 1) ex[i]-- ; else
if (epos[i] == 2) ex[i]++ ; else
if (epos[i] == 3) ey[i]-- ; else
if (epos[i] == 4) ey[i]++ ;
}
if (x == ex[i] && y == ey[i]) // "битва"
{
if (ehp[i] > 1)
{
ehp[i] -= dm;
(edm[i] < armor) ?
hp -= 0 :
hp -= edm[i]-armor;
} else {
ex[i] = ey[i] = -1;
xp += exp[i];
ehp[i] = 12;
}
}
if (!ght) // если не призрак проверять столкновение игрока с врагами
{
if (HIT 1) y++ ;else
if (HIT 2) x-- ;else
if (HIT 3) y-- ;else
if (HIT 4) x++ ;
}
}
if (!ght) // то же, но со стенами
{
TOUCH 1 I y++ J
TOUCH 2 I x-- J
TOUCH 3 I y-- J
TOUCH 4 ) x++ ;
}
}
5. ménu
Urang saukur mintonkeun menu nu, nomeran item, sarta ngagunakeun getkey () pikeun prosés pilihan pamuter urang. Urang nulis status bar karakter urang, nerapkeun menu leveling, nulis backstory, sarta kami meunang naon atuh disebut "Subsoil".
kacindekan
Ieu hal kawas kieu. Anjeun tiasa maénkeun éta , ngabongkar sareng ngajalankeun sapertos kieu:
$ sudo chmod +x Subsoil-1.0/Subsoil$ Subsoil-1.0/Subsoil, atawa, tungtungna diideuan, nulis diri hiji petualangan tina liking anjeun sorangan. Kuring ngingetkeun anjeun sateuacanna: kaulinan abdi teu gampang!
Tumbu
, .
sumber: www.habr.com