Wonke umuntu uzozishayela nini izimoto zikagesi?

NgoJanuwari 11, 1914, i-New York Times yashicilela isitatimende sikaHenry Ford:

β€œNgiyethemba ukuthi ngonyaka sizoqala ukukhiqiza imoto esebenza ngogesi. Angithandi ukukhuluma ngezinto ezisasele unyaka, kodwa ngifuna ukunitshela okuthile ngezinhlelo zami. Iqiniso liwukuthi mina noMnu. Edison sesisebenze iminyaka eminingana ekwakhiweni kwezimoto zikagesi ezishibhile nezisebenzayo. Zenziwa njengesivivinyo, futhi sanelisekile ukuthi indlela eya empumelelweni icacile. Inkinga ngezimoto zikagesi kuze kube manje kube wukwenza ibhethri elingasindi elikwazi ukusebenza amabanga amade ngaphandle kokulishajwa. UMnu. Edison usenesikhathi eside ehlola ibhethri elinjalo."

Kodwa kukhona okungahambanga kahle...

Wonke umuntu uzozishayela nini izimoto zikagesi?
Thomas Edison eDetroit Electric

Le ncwadi iwukuqhubeka okunengqondo kwesihloko sami sangaphambilini "Ucwaningo lwezokuthutha lusebenza njengomthetho wokuthuthukiswa kwemboni".

Wonke umuntu uzozishayela nini izimoto zikagesi?

lapho ipharamitha r kuthinta izinga lokukhula kwesabelo semakethe, njengoba ku-index ye-exponential - ephakeme le coefficient, ngokushesha ubuchwepheshe obusha buzonqoba imakethe, i.e. njalo ngonyaka ubuchwepheshe kufanele buthakazelise abantu abaningi ngokulula kwabo., K i-coefficient echaza amandla okukhula obuchwepheshe obusha, i.e. ngamavelu aphansi ka-K, ubuchwepheshe ngeke bukwazi ukuthwebula yonke imakethe, kodwa buzokwazi ukuzuza kuphela ingxenye yemakethe lapho izothakazelisa kakhulu kunobuchwepheshe obudlule.

Isitatimende senkinga ukuthola amapharamitha adingekayo we-logistic equation evumela ukubikezela ukuthuthuka kwemboni yezimoto zikagesi zabagibeli:

  • "Unyaka we-Zero" - unyaka lapho ingxenye yezimoto ezithengiswayo emhlabeni izoba ne-motor kagesi (Π 0=0,5, t = 0);
  • izinga lokukhula kwesabelo semakethe (r) izimoto zikagesi.

Ake sicabangele:

  • izimoto zikagesi zizosusa ngokuphelele izimoto ezinenjini evuthayo yangaphakathi (ICE) emakethe (K = 1), njengoba ngingawuboni umugqa ozovumela ukuhlukanisa imakethe yezimoto zabagibeli.

    Imakethe yezimoto ezinzima kanye nemishini ekhethekile ayizange inakwe lapho kuhlanganiswa imodeli, ngakho-ke akukabikho imakethe yezimoto zikagesi ngaphakathi kwale mboni.

  • manje siphila β€œesikhathini esingesihle” (P(t)<0) futhi emsebenzini sizosebenzisa i-offset ehlobene β€œnonyaka onguziro” wesikhathi sethu (t-t0).

Izibalo zokuthengiswa kwezimoto zithathwe ku lapha.

Izibalo zokuthengiswa kwezimoto zikagesi zithathwe ku lapha.

Izibalo ngaphambi kuka-2012 ezimotweni zikagesi ziyindlala kakhulu futhi ngeke zicatshangelwe ocwaningweni.

Ngenxa yalokho, sinedatha elandelayo:

Wonke umuntu uzozishayela nini izimoto zikagesi?

I-Year Zero kanye nohlelo Lokusesha I-Coefficient Yokukhula Kwemakethe

import matplotlib.pyplot as plt
import numpy as np
import math

x = np.linspace(2012, 2019, 8)
y1 = np.array([60936407, 63429200, 65708230, 66314155, 69464432, 70694834, 68690468,  64341693]) # ΠΊΠΎΠ»-Π²ΠΎ ΠΏΡ€ΠΎΠΈΠ·Π²Π΅Π΄Π΅Π½Π½Ρ‹Ρ… Π»Π΅Π³ΠΊΠΎΠ²Ρ‹Ρ… машин
y2 = np.array([52605, 97507, 320713, 550297, 777495, 1227117, 2018247,  1940147]) # ΠΊΠΎΠ»-Π²ΠΎ ΠΏΡ€ΠΎΠΈΠ·Π²Π΅Π΄Π΅Π½Π½Ρ‹Ρ… Π»Π΅Π³ΠΊΠΎΠ²Ρ‹Ρ… элСктромобилСй
y = y2/y1 #доля элСктромобилСй Π² ΠΎΠ±Ρ‰Π΅ΠΌ производствС Π°Π²Ρ‚ΠΎΠΌΠΎΠ±ΠΈΠ»Π΅ΠΉ

ymax=1 #ΠΏΠ΅Ρ€Π²ΠΎΠ½Π°Ρ‡Π°Π»ΡŒΠ½ΠΎΠ΅ максимальноС ΠΎΡ‚ΠΊΠ»ΠΎΠ½Π΅Π½ΠΈΠ΅ статистичСских Π΄Π°Π½Π½Ρ‹Ρ… ΠΎΡ‚ Π·Π½Π°Ρ‡Π΅Π½ΠΈΠΉ Ρ„ΡƒΠ½ΠΊΡ†ΠΈΠΈ
Gmax=2025 #Π³ΠΎΠ΄ для Π½Π°Ρ‡Π°Π»ΠΎ поиска "Π½ΡƒΠ»Π΅Π²ΠΎΠ³ΠΎ Π³ΠΎΠ΄Π°"
rmax=0.35 #Π½Π°Ρ‡Π°Π»ΡŒΠ½Ρ‹ΠΉ коэффициСнт
k=1 #принят "1" ΠΈΠ· прСдпосылки, Ρ‡Ρ‚ΠΎ элСктромобили ΠΏΠΎΠ»Π½ΠΎΡΡ‚ΡŒΡŽ замСнят Π»Π΅Π³ΠΊΠΎΠ²Ρ‹Π΅ Π°Π²Ρ‚ΠΎΠΌΠΎΠ±ΠΈΠ»ΠΈ с Π”Π’Π‘
p0=0.5 # ΠΏΡ€ΠΎΡ†Π΅Π½Ρ‚ Ρ€Ρ‹Π½ΠΊΠ° Π² "Π½ΡƒΠ»Π΅Π²ΠΎΠΉ Π³ΠΎΠ΄"
for j in range(10): # Ρ†ΠΈΠΊΠ» ΠΏΠ΅Ρ€Π΅Π±ΠΎΡ€Π° "Π½ΡƒΠ»Π΅Π²Ρ‹Ρ… Π³ΠΎΠ΄ΠΎΠ²"
    x0=2025+j
    r=0.35
    
    for i in range(10): # Ρ†ΠΈΠΊΠ» ΠΏΠ΅Ρ€Π΅Π±ΠΎΡ€Π° коэффициСнта Π² ΠΊΠ°ΠΆΠ΄ΠΎΠΌ "Π½ΡƒΠ»Π΅Π²ΠΎΠΌ Π³ΠΎΠ΄Ρƒ"
            r=0.25+0.02*i
            y4=k*p0*math.e**(r*(x-x0))/(k+p0*(math.e**(r*(x-x0))-1))-y 
           # print(str(x0).ljust(20), str(r).ljust(20), max(abs(y4))) 
            if max(abs(y4))<=ymax: # поиск минимального ΠΈΠ· ΠΌΠ°ΠΊΡΠΈΠΌΠ°Π»ΡŒΠ½Ρ‹Ρ… ΠΎΡ‚ΠΊΠ»ΠΎΠ½Π΅Π½ΠΈΠΉ Π²Π½ΡƒΡ‚Ρ€ΠΈ ΠΊΠ°ΠΆΠ΄ΠΎΠ³ΠΎ Π³ΠΎΠ΄Π° ΠΏΡ€ΠΈ ΠΊΠ°ΠΆΠ΄ΠΎΠΌ коэффициСнтС r
                ymax=max(abs(y4))
                Gmax=x0
                rmax=r
print(str(Gmax).ljust(20), str(rmax).ljust(20), ymax) # Π²Ρ‹Π²ΠΎΠ΄ "Π½ΡƒΠ»Π΅Π²ΠΎΠ³ΠΎ Π³ΠΎΠ΄Π°", коэффициСнта r ΠΈ максимального ΠΈΠ· ΠΎΡ‚ΠΊΠ»ΠΎΠ½Π΅Π½ΠΈΠΉ ΠΎΡ‚ Ρ„ΡƒΠ½ΠΊΡ†ΠΈΠΈ

Njengomphumela wohlelo, amanani alandelayo akhethiwe:
Unyaka onguziro ngu-2028.
Isici sokukhula - 0.37

Ukuchezuka okukhulu kwedatha yezibalo kusuka kunani lomsebenzi ngu-0.005255.

Igrafu yomsebenzi osesigabeni phakathi kuka-2012 no-2019 imi kanje:

Wonke umuntu uzozishayela nini izimoto zikagesi?

Igrafu yokugcina enesibikezelo esifika ku-2050 ibukeka kanje:

Wonke umuntu uzozishayela nini izimoto zikagesi?

Ishadi libonisa ukunqanyulwa kwe-99% yayo yonke imakethe, i.e. ngo-2040, imoto kagesi izoshintsha ngokuphelele izimoto ngezinjini ezivuthayo zangaphakathi.

Uhlelo lokusebenza lwe-Graphing

import matplotlib.pyplot as plt
import numpy as np
import math

x = np.linspace(2012, 2019, 8)
y1 = np.array([60936407, 63429200, 65708230, 66314155, 69464432, 70694834, 68690468,  64341693])
y2 = np.array([52605, 97507, 320713, 550297, 777495, 1227117, 2018247,  1940147])
y = y2/y1

k=1
p0=0.5

x0=2028   
r=0.37 
y1=k*p0*math.e**(r*(x-x0))/(k+p0*(math.e**(r*(x-x0))-1))
#Π‘Ρ‚Ρ€ΠΎΠΈΠΌ Π³Ρ€Π°Ρ„ΠΈΠΊ Ρ„ΡƒΠ½ΠΊΡ†ΠΈΠΈ Π½Π° ΠΎΡ‚Ρ€Π΅Π·ΠΊΠ΅ ΠΌΠ΅ΠΆΠ΄Ρƒ 2012 ΠΈ 2019 Π³ΠΎΠ΄Π°ΠΌΠΈ
fig, ax = plt.subplots(figsize=(30, 20), facecolor="#f5f5f5")
plt.grid()
ax.plot(x, y, 'o', color='tab:brown') 
ax.plot(x, y1)
#Π‘Ρ‚Ρ€ΠΎΠΈΠΌ Π³Ρ€Π°Ρ„ΠΈΠΊ Ρ„ΡƒΠ½ΠΊΡ†ΠΈΠΈ Π½Π° ΠΎΡ‚Ρ€Π΅Π·ΠΊΠ΅ ΠΌΠ΅ΠΆΠ΄Ρƒ 2010 ΠΈ 2050 Π³ΠΎΠ΄Π°ΠΌΠΈ
x = np.linspace(2010, 2050)
y2 = [k*p0*math.e**(r*(i-x0))/(k+p0*(math.e**(r*(i-x0))-1)) for i in x]
y3 = 0.99+0*x
fig, ax = plt.subplots(figsize=(30, 20), facecolor="#f5f5f5") 
ax.set_xlim([2010, 2050])
ax.set_ylim([0, 1])
plt.grid()             
plt.plot(x, y2, x, y3)

okutholakele

Ngokulandela umqondo ofanayo njengalapho ngichaza umlando wokuthuthukiswa kwezimoto ze-ICE, ngazama ukubikezela ukuthuthukiswa kwemboni yezimoto zikagesi zabagibeli ngisebenzisa idatha yezibalo etholakalayo.

Imiphumela etholakele iphakamisa ukuthi ngo-2030 ingxenye yezimoto ezidayiswa emhlabeni izobe isinenjini kagesi, kanti ngo-2040 izimoto zabagibeli ezinezinjini ezivuthayo zangaphakathi zizobe zingasekho.

Yiqiniso, ngemva kuka-2030, abanye abantu bazoshayela izimoto zegesi abazithenge ngaphambi kuka-2030, kodwa bazokwazi ukuthi ukuthenga kwabo okulandelayo kuzoba yimoto kagesi.
Isici sokukhula sezimoto zikagesi siphindwe izikhathi ezingu-4 kunesici sokukhula kwezimoto ezinezinjini zomlilo zangaphakathi, okubonisa ukuthi ubuchwepheshe obusha buya ngokuya bungena ezimpilweni zethu, bube yingxenye evamile yokuphila kwethu kwansuku zonke (cabanga ngomakhalekhukhwini lapha).

Eminyakeni ezayo, inkinga u-Edison akakwazanga ukuyixazulula kufanele ixazululwe - ibhethri elinamandla ngokwanele elizokwandisa ububanzi phakathi kweziteshi zokushaja.

Ukwakha inethiwekhi yeziteshi zokushaja ezilingana nenethiwekhi yegalaji yegesi ekhona, kuyadingeka ukuthuthukisa amanethiwekhi kagesi akhona emadolobheni amakhulu nasemigwaqweni emikhulu.

Futhi, ukukhula kokuthengiswa kwezimoto zikagesi kuzophazamiseka I-Jevans indida, kodwa futhi kwaphazamisa uwoyela phakathi nesidingo esiqatha samalahle.

PS
Uma u-Edison ekwazi ukuxazulula inkinga ebekwe phambi kwakhe, "iminyaka yamafutha" yayingeke iqale ...

Abasebenzisi ababhalisiwe kuphela abangabamba iqhaza kuhlolovo. Ngena ngemvume, wamukelekile.

Wonke umuntu uzozishayela nini izimoto zikagesi?

  • 9,5%ngo-2030 wonke umuntu uzoshintshela ezimotweni zikagesi, hhayi uhhafu

  • 20,0%ngo-2040 wonke umuntu nakanjani uzoshintshela ezimotweni zikagesi38

  • 48,4%hhayi ngaphambi kuka-2050

  • 22,1%imoto kagesi ayisoze yathatha indawo yemoto kaphethiloli42

Bangu-190 abasebenzisi abavotile. Abasebenzisi abangu-37 bagobile.

Source: www.habr.com

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